2(3x+4)+65=10x+6-4x+67

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Solution for 2(3x+4)+65=10x+6-4x+67 equation: 



2(3x+4)+65=10x+6-4x+67

We move all terms to the left:

2(3x+4)+65-(10x+6-4x+67)=0

We add all the numbers together, and all the variables

2(3x+4)-(6x+73)+65=0

We multiply parentheses

6x-(6x+73)+8+65=0

We get rid of parentheses

6x-6x-73+8+65=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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