2(3x+4)+6=32

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Solution for 2(3x+4)+6=32 equation: 



2(3x+4)+6=32

We move all terms to the left:

2(3x+4)+6-(32)=0

We add all the numbers together, and all the variables

2(3x+4)-26=0

We multiply parentheses

6x+8-26=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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