2(3x+4)-(x-4)=32

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Solution for 2(3x+4)-(x-4)=32 equation: 



2(3x+4)-(x-4)=32

We move all terms to the left:

2(3x+4)-(x-4)-(32)=0

We multiply parentheses

6x-(x-4)+8-32=0

We get rid of parentheses

6x-x+4+8-32=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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