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2(3x+4)-5=3(2x-1)+1
We move all terms to the left:
2(3x+4)-5-(3(2x-1)+1)=0
We multiply parentheses
6x-(3(2x-1)+1)+8-5=0
We calculate terms in parentheses: -(3(2x-1)+1), so:We add all the numbers together, and all the variables
3(2x-1)+1
We multiply parentheses
6x-3+1
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
6x-(6x-2)+3=0
We get rid of parentheses
6x-6x+2+3=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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