2(3x+4)-5=9+3(x-1)

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Solution for 2(3x+4)-5=9+3(x-1) equation: 



2(3x+4)-5=9+3(x-1)

We move all terms to the left:

2(3x+4)-5-(9+3(x-1))=0

We multiply parentheses

6x-(9+3(x-1))+8-5=0



We calculate terms in parentheses: -(9+3(x-1)), so:

9+3(x-1)

determiningTheFunctionDomain
3(x-1)+9

We multiply parentheses

3x-3+9

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

6x-(3x+6)+3=0

We get rid of parentheses

6x-3x-6+3=0

We add all the numbers together, and all the variables

3x-3=0

We move all terms containing x to the left, all other terms to the right

3x=3

x=3/3

x=1

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