2(3x+4)-6=2(2x-4)+20

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Solution for 2(3x+4)-6=2(2x-4)+20 equation: 



2(3x+4)-6=2(2x-4)+20

We move all terms to the left:

2(3x+4)-6-(2(2x-4)+20)=0

We multiply parentheses

6x-(2(2x-4)+20)+8-6=0



We calculate terms in parentheses: -(2(2x-4)+20), so:

2(2x-4)+20

We multiply parentheses

4x-8+20

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

6x-(4x+12)+2=0

We get rid of parentheses

6x-4x-12+2=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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