2(3x+4)-8=8x+7-x

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Solution for 2(3x+4)-8=8x+7-x equation: 



2(3x+4)-8=8x+7-x

We move all terms to the left:

2(3x+4)-8-(8x+7-x)=0

We add all the numbers together, and all the variables

2(3x+4)-(7x+7)-8=0

We multiply parentheses

6x-(7x+7)+8-8=0

We get rid of parentheses

6x-7x-7+8-8=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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