2(3x+4)8+10x=72

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Solution for 2(3x+4)8+10x=72 equation: 



2(3x+4)8+10x=72

We move all terms to the left:

2(3x+4)8+10x-(72)=0

We add all the numbers together, and all the variables

10x+2(3x+4)8-72=0

We multiply parentheses

10x+48x+64-72=0

We add all the numbers together, and all the variables

58x-8=0

We move all terms containing x to the left, all other terms to the right

58x=8

x=8/58

x=4/29

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