2(3x+4)=(3x+9)+(2x+11)

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Solution for 2(3x+4)=(3x+9)+(2x+11) equation: 



2(3x+4)=(3x+9)+(2x+11)

We move all terms to the left:

2(3x+4)-((3x+9)+(2x+11))=0

We multiply parentheses

6x-((3x+9)+(2x+11))+8=0



We calculate terms in parentheses: -((3x+9)+(2x+11)), so:

(3x+9)+(2x+11)

We get rid of parentheses

3x+2x+9+11

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We get rid of parentheses

6x-5x-20+8=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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