2(3x+4)=(3x+9)+(2x+11)

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Solution for 2(3x+4)=(3x+9)+(2x+11) equation:



2(3x+4)=(3x+9)+(2x+11)
We move all terms to the left:
2(3x+4)-((3x+9)+(2x+11))=0
We multiply parentheses
6x-((3x+9)+(2x+11))+8=0
We calculate terms in parentheses: -((3x+9)+(2x+11)), so:
(3x+9)+(2x+11)
We get rid of parentheses
3x+2x+9+11
We add all the numbers together, and all the variables
5x+20
Back to the equation:
-(5x+20)
We get rid of parentheses
6x-5x-20+8=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12

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