2(3x+4)=1/2(12x+16

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Solution for 2(3x+4)=1/2(12x+16 equation: 



2(3x+4)=1/2(12x+16

We move all terms to the left:

2(3x+4)-(1/2(12x+16)=0



Domain of the equation: 2(12x+16)!=0

x∈R



We multiply parentheses

6x-(1/2(12x+16)+8=0

We multiply all the terms by the denominator


6x*2(12x+16)+8-(1=0

We add all the numbers together, and all the variables

6x*2(12x+16)=0

Wy multiply elements

12x^2(1=0

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