2(3x+4)=3(2x-3)/4

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Solution for 2(3x+4)=3(2x-3)/4 equation: 



2(3x+4)=3(2x-3)/4

We move all terms to the left:

2(3x+4)-(3(2x-3)/4)=0

We multiply parentheses

6x-(3(2x-3)/4)+8=0

We multiply all the terms by the denominator


6x*4)-(3(2x-3)+8*4)=0

We add all the numbers together, and all the variables

6x*4)-(3(2x-3)=0

Wy multiply elements

24x^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{48}=0$

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