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2(3x+4)=3(2x-4)
We move all terms to the left:
2(3x+4)-(3(2x-4))=0
We multiply parentheses
6x-(3(2x-4))+8=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
6x-6x+12+8=0
We add all the numbers together, and all the variables
20!=0
There is no solution for this equation
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