2(3x+4)=3(x+1)+11

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Solution for 2(3x+4)=3(x+1)+11 equation: 



2(3x+4)=3(x+1)+11

We move all terms to the left:

2(3x+4)-(3(x+1)+11)=0

We multiply parentheses

6x-(3(x+1)+11)+8=0



We calculate terms in parentheses: -(3(x+1)+11), so:

3(x+1)+11

We multiply parentheses

3x+3+11

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We get rid of parentheses

6x-3x-14+8=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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