2(3x+4)=3x+x+20

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Solution for 2(3x+4)=3x+x+20 equation: 



2(3x+4)=3x+x+20

We move all terms to the left:

2(3x+4)-(3x+x+20)=0

We add all the numbers together, and all the variables

2(3x+4)-(4x+20)=0

We multiply parentheses

6x-(4x+20)+8=0

We get rid of parentheses

6x-4x-20+8=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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