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2(3x+4)=6(1+x)+2
We move all terms to the left:
2(3x+4)-(6(1+x)+2)=0
We add all the numbers together, and all the variables
2(3x+4)-(6(x+1)+2)=0
We multiply parentheses
6x-(6(x+1)+2)+8=0
We calculate terms in parentheses: -(6(x+1)+2), so:We get rid of parentheses
6(x+1)+2
We multiply parentheses
6x+6+2
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
6x-6x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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