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2(3x+4)=9-(x+5)+3
We move all terms to the left:
2(3x+4)-(9-(x+5)+3)=0
We multiply parentheses
6x-(9-(x+5)+3)+8=0
We calculate terms in parentheses: -(9-(x+5)+3), so:We get rid of parentheses
9-(x+5)+3
determiningTheFunctionDomain -(x+5)+9+3
We add all the numbers together, and all the variables
-(x+5)+12
We get rid of parentheses
-x-5+12
We add all the numbers together, and all the variables
-1x+7
Back to the equation:
-(-1x+7)
6x+1x-7+8=0
We add all the numbers together, and all the variables
7x+1=0
We move all terms containing x to the left, all other terms to the right
7x=-1
x=-1/7
x=-1/7
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