2(3x+4)=9x+28

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Solution for 2(3x+4)=9x+28 equation: 



2(3x+4)=9x+28

We move all terms to the left:

2(3x+4)-(9x+28)=0

We multiply parentheses

6x-(9x+28)+8=0

We get rid of parentheses

6x-9x-28+8=0

We add all the numbers together, and all the variables

-3x-20=0

We move all terms containing x to the left, all other terms to the right

-3x=20

x=20/-3

x=-6+2/3

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