2(3x+4x+1)=58

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Solution for 2(3x+4x+1)=58 equation: 



2(3x+4x+1)=58

We move all terms to the left:

2(3x+4x+1)-(58)=0

We add all the numbers together, and all the variables

2(7x+1)-58=0

We multiply parentheses

14x+2-58=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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