2(3x+5)+1=(-4x+5)+(7x-8)

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Solution for 2(3x+5)+1=(-4x+5)+(7x-8) equation: 



2(3x+5)+1=(-4x+5)+(7x-8)

We move all terms to the left:

2(3x+5)+1-((-4x+5)+(7x-8))=0

We multiply parentheses

6x-((-4x+5)+(7x-8))+10+1=0



We calculate terms in parentheses: -((-4x+5)+(7x-8)), so:

(-4x+5)+(7x-8)

We get rid of parentheses

-4x+7x+5-8

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

6x-(3x-3)+11=0

We get rid of parentheses

6x-3x+3+11=0

We add all the numbers together, and all the variables

3x+14=0

We move all terms containing x to the left, all other terms to the right

3x=-14

x=-14/3

x=-4+2/3

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