2(3x+5)-(4x-7)=3(x-5)+x+10

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Solution for 2(3x+5)-(4x-7)=3(x-5)+x+10 equation: 



2(3x+5)-(4x-7)=3(x-5)+x+10

We move all terms to the left:

2(3x+5)-(4x-7)-(3(x-5)+x+10)=0

We multiply parentheses

6x-(4x-7)-(3(x-5)+x+10)+10=0

We get rid of parentheses

6x-4x-(3(x-5)+x+10)+7+10=0



We calculate terms in parentheses: -(3(x-5)+x+10), so:

3(x-5)+x+10

We add all the numbers together, and all the variables

x+3(x-5)+10

We multiply parentheses

x+3x-15+10

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

2x-(4x-5)+17=0

We get rid of parentheses

2x-4x+5+17=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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