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2(3x+5)=-4(2x-3)+5x
We move all terms to the left:
2(3x+5)-(-4(2x-3)+5x)=0
We multiply parentheses
6x-(-4(2x-3)+5x)+10=0
We calculate terms in parentheses: -(-4(2x-3)+5x), so:We get rid of parentheses
-4(2x-3)+5x
We add all the numbers together, and all the variables
5x-4(2x-3)
We multiply parentheses
5x-8x+12
We add all the numbers together, and all the variables
-3x+12
Back to the equation:
-(-3x+12)
6x+3x-12+10=0
We add all the numbers together, and all the variables
9x-2=0
We move all terms containing x to the left, all other terms to the right
9x=2
x=2/9
x=2/9
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