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2(3x+5)=-5(2x-3)+4x
We move all terms to the left:
2(3x+5)-(-5(2x-3)+4x)=0
We multiply parentheses
6x-(-5(2x-3)+4x)+10=0
We calculate terms in parentheses: -(-5(2x-3)+4x), so:We get rid of parentheses
-5(2x-3)+4x
We add all the numbers together, and all the variables
4x-5(2x-3)
We multiply parentheses
4x-10x+15
We add all the numbers together, and all the variables
-6x+15
Back to the equation:
-(-6x+15)
6x+6x-15+10=0
We add all the numbers together, and all the variables
12x-5=0
We move all terms containing x to the left, all other terms to the right
12x=5
x=5/12
x=5/12
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