2(3x+5)=10(x+1)-4

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Solution for 2(3x+5)=10(x+1)-4 equation: 



2(3x+5)=10(x+1)-4

We move all terms to the left:

2(3x+5)-(10(x+1)-4)=0

We multiply parentheses

6x-(10(x+1)-4)+10=0



We calculate terms in parentheses: -(10(x+1)-4), so:

10(x+1)-4

We multiply parentheses

10x+10-4

We add all the numbers together, and all the variables

10x+6

Back to the equation:

-(10x+6)



We get rid of parentheses

6x-10x-6+10=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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