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2(3x+5)=3(2x-4)-2x
We move all terms to the left:
2(3x+5)-(3(2x-4)-2x)=0
We multiply parentheses
6x-(3(2x-4)-2x)+10=0
We calculate terms in parentheses: -(3(2x-4)-2x), so:We get rid of parentheses
3(2x-4)-2x
We add all the numbers together, and all the variables
-2x+3(2x-4)
We multiply parentheses
-2x+6x-12
We add all the numbers together, and all the variables
4x-12
Back to the equation:
-(4x-12)
6x-4x+12+10=0
We add all the numbers together, and all the variables
2x+22=0
We move all terms containing x to the left, all other terms to the right
2x=-22
x=-22/2
x=-11
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