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2(3x+5)=4(3x-11)
We move all terms to the left:
2(3x+5)-(4(3x-11))=0
We multiply parentheses
6x-(4(3x-11))+10=0
We calculate terms in parentheses: -(4(3x-11)), so:We get rid of parentheses
4(3x-11)
We multiply parentheses
12x-44
Back to the equation:
-(12x-44)
6x-12x+44+10=0
We add all the numbers together, and all the variables
-6x+54=0
We move all terms containing x to the left, all other terms to the right
-6x=-54
x=-54/-6
x=+9
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