2(3x+5)=40-2x

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Solution for 2(3x+5)=40-2x equation: 



2(3x+5)=40-2x

We move all terms to the left:

2(3x+5)-(40-2x)=0

We add all the numbers together, and all the variables

2(3x+5)-(-2x+40)=0

We multiply parentheses

6x-(-2x+40)+10=0

We get rid of parentheses

6x+2x-40+10=0

We add all the numbers together, and all the variables

8x-30=0

We move all terms containing x to the left, all other terms to the right

8x=30

x=30/8

x=3+3/4

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