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2(3x+5)=7(x-3)
We move all terms to the left:
2(3x+5)-(7(x-3))=0
We multiply parentheses
6x-(7(x-3))+10=0
We calculate terms in parentheses: -(7(x-3)), so:We get rid of parentheses
7(x-3)
We multiply parentheses
7x-21
Back to the equation:
-(7x-21)
6x-7x+21+10=0
We add all the numbers together, and all the variables
-1x+31=0
We move all terms containing x to the left, all other terms to the right
-x=-31
x=-31/-1
x=+31
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