2(3x+6)=3(3x2)

Solution for 2(3x+6)=3(3x2) equation:

2(3x+6)=3(3x^2)

We move all terms to the left:

2(3x+6)-(3(3x^2))=0

determiningTheFunctionDomain
2(3x+6)-33x^2=0

We add all the numbers together, and all the variables

-33x^2+2(3x+6)=0

We multiply parentheses

-33x^2+6x+12=0

a = -33; b = 6; c = +12;
Δ = b2-4ac
Δ = 62-4·(-33)·12
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18\sqrt{5}}{2*-33}=\frac{-6-18\sqrt{5}}{-66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18\sqrt{5}}{2*-33}=\frac{-6+18\sqrt{5}}{-66}
$