2(3x+7)=58-2(5x-2)

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Solution for 2(3x+7)=58-2(5x-2) equation: 



2(3x+7)=58-2(5x-2)

We move all terms to the left:

2(3x+7)-(58-2(5x-2))=0

We multiply parentheses

6x-(58-2(5x-2))+14=0



We calculate terms in parentheses: -(58-2(5x-2)), so:

58-2(5x-2)

determiningTheFunctionDomain
-2(5x-2)+58

We multiply parentheses

-10x+4+58

We add all the numbers together, and all the variables

-10x+62

Back to the equation:

-(-10x+62)



We get rid of parentheses

6x+10x-62+14=0

We add all the numbers together, and all the variables

16x-48=0

We move all terms containing x to the left, all other terms to the right

16x=48

x=48/16

x=3

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