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2(3x+x)-(5x-2)=12-2(6x-12)
We move all terms to the left:
2(3x+x)-(5x-2)-(12-2(6x-12))=0
We add all the numbers together, and all the variables
2(+4x)-(5x-2)-(12-2(6x-12))=0
We multiply parentheses
8x-(5x-2)-(12-2(6x-12))=0
We get rid of parentheses
8x-5x-(12-2(6x-12))+2=0
We calculate terms in parentheses: -(12-2(6x-12)), so:We add all the numbers together, and all the variables
12-2(6x-12)
determiningTheFunctionDomain -2(6x-12)+12
We multiply parentheses
-12x+24+12
We add all the numbers together, and all the variables
-12x+36
Back to the equation:
-(-12x+36)
3x-(-12x+36)+2=0
We get rid of parentheses
3x+12x-36+2=0
We add all the numbers together, and all the variables
15x-34=0
We move all terms containing x to the left, all other terms to the right
15x=34
x=34/15
x=2+4/15
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