2(3x+x)=64

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Solution for 2(3x+x)=64 equation: 



2(3x+x)=64

We move all terms to the left:

2(3x+x)-(64)=0

We add all the numbers together, and all the variables

2(+4x)-64=0

We multiply parentheses

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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