2(3x-+4)-3(x+1)=4(x-4)+23

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Solution for 2(3x-+4)-3(x+1)=4(x-4)+23 equation: 



2(3x-+4)-3(x+1)=4(x-4)+23

We move all terms to the left:

2(3x-+4)-3(x+1)-(4(x-4)+23)=0

We add all the numbers together, and all the variables

2(+3x)-3(x+1)-(4(x-4)+23)=0

We multiply parentheses

6x-3x-(4(x-4)+23)-3=0



We calculate terms in parentheses: -(4(x-4)+23), so:

4(x-4)+23

We multiply parentheses

4x-16+23

We add all the numbers together, and all the variables

4x+7

Back to the equation:

-(4x+7)



We add all the numbers together, and all the variables

3x-(4x+7)-3=0

We get rid of parentheses

3x-4x-7-3=0

We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10

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