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2(3x-1)(3x-1)=0
We multiply parentheses ..
2(+9x^2-3x-3x+1)=0
We multiply parentheses
18x^2-6x-6x+2=0
We add all the numbers together, and all the variables
18x^2-12x+2=0
a = 18; b = -12; c = +2;
Δ = b2-4ac
Δ = -122-4·18·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{12}{36}=1/3$
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