2(3x-1)+2(4c+5)=8

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Solution for 2(3x-1)+2(4c+5)=8 equation:


Simplifying
2(3x + -1) + 2(4c + 5) = 8

Reorder the terms:
2(-1 + 3x) + 2(4c + 5) = 8
(-1 * 2 + 3x * 2) + 2(4c + 5) = 8
(-2 + 6x) + 2(4c + 5) = 8

Reorder the terms:
-2 + 6x + 2(5 + 4c) = 8
-2 + 6x + (5 * 2 + 4c * 2) = 8
-2 + 6x + (10 + 8c) = 8

Reorder the terms:
-2 + 10 + 8c + 6x = 8

Combine like terms: -2 + 10 = 8
8 + 8c + 6x = 8

Add '-8' to each side of the equation.
8 + 8c + -8 + 6x = 8 + -8

Reorder the terms:
8 + -8 + 8c + 6x = 8 + -8

Combine like terms: 8 + -8 = 0
0 + 8c + 6x = 8 + -8
8c + 6x = 8 + -8

Combine like terms: 8 + -8 = 0
8c + 6x = 0

Solving
8c + 6x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6x' to each side of the equation.
8c + 6x + -6x = 0 + -6x

Combine like terms: 6x + -6x = 0
8c + 0 = 0 + -6x
8c = 0 + -6x
Remove the zero:
8c = -6x

Divide each side by '8'.
c = -0.75x

Simplifying
c = -0.75x

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