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2(3x-1)+2=4(x+3)
We move all terms to the left:
2(3x-1)+2-(4(x+3))=0
We multiply parentheses
6x-(4(x+3))-2+2=0
We calculate terms in parentheses: -(4(x+3)), so:We add all the numbers together, and all the variables
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
6x-(4x+12)=0
We get rid of parentheses
6x-4x-12=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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