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2(3x-1)+3(5x-6)=5(x+3)+2(3x+2)+1
We move all terms to the left:
2(3x-1)+3(5x-6)-(5(x+3)+2(3x+2)+1)=0
We multiply parentheses
6x+15x-(5(x+3)+2(3x+2)+1)-2-18=0
We calculate terms in parentheses: -(5(x+3)+2(3x+2)+1), so:We add all the numbers together, and all the variables
5(x+3)+2(3x+2)+1
We multiply parentheses
5x+6x+15+4+1
We add all the numbers together, and all the variables
11x+20
Back to the equation:
-(11x+20)
21x-(11x+20)-20=0
We get rid of parentheses
21x-11x-20-20=0
We add all the numbers together, and all the variables
10x-40=0
We move all terms containing x to the left, all other terms to the right
10x=40
x=40/10
x=4
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