2(3x-1)+3(x+20)=2(3)+6(2x+4)

Solution for 2(3x-1)+3(x+20)=2(3)+6(2x+4) equation:

2(3x-1)+3(x+20)=2(3)+6(2x+4)

We simplify the equation to the form, which is simple to understand 
2(3x-1)+3(x+20)=2(3)+6(2x+4)

Reorder the terms in parentheses
+(+6x-2)+3*(x+20)=2*(3)+6*(2x+4)

Remove unnecessary parentheses
+6x-2+3+*(+x+20+)=+2+*(+3+)+6+*(+2x+4+)

Reorder the terms in parentheses
+6x-2+(+3x+60)=2*(3)+6*(2x+4)

Remove unnecessary parentheses
+6x-2+3x+60=+2+*(+3+)+6+*(+2x+4+)

Reorder the terms in parentheses
+6x-2+3x+60=+(+6)+6*(2x+4)

Remove unnecessary parentheses
+6x-2+3x+60=+6+6+*(+2x+4+)

Reorder the terms in parentheses
+6x-2+3x+60=+6+(+12x+24)

Remove unnecessary parentheses
+6x-2+3x+60=+6+12x+24

We move all terms containing x to the left and all other terms to the right. 
+6x+3x-12x=+6+24+2-60

We simplify left and right side of the equation. 
-3x=-28

We divide both sides of the equation by -3 to get x. 
x=9.3333333333333