2(3x-1)+4=6+(2x+1)4

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Solution for 2(3x-1)+4=6+(2x+1)4 equation: 



2(3x-1)+4=6+(2x+1)4

We move all terms to the left:

2(3x-1)+4-(6+(2x+1)4)=0

We multiply parentheses

6x-(6+(2x+1)4)-2+4=0



We calculate terms in parentheses: -(6+(2x+1)4), so:

6+(2x+1)4

determiningTheFunctionDomain
(2x+1)4+6

We multiply parentheses

8x+4+6

We add all the numbers together, and all the variables

8x+10

Back to the equation:

-(8x+10)



We add all the numbers together, and all the variables

6x-(8x+10)+2=0

We get rid of parentheses

6x-8x-10+2=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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