2(3x-1)+5=-3(x+2)-13

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Solution for 2(3x-1)+5=-3(x+2)-13 equation: 



2(3x-1)+5=-3(x+2)-13

We move all terms to the left:

2(3x-1)+5-(-3(x+2)-13)=0

We multiply parentheses

6x-(-3(x+2)-13)-2+5=0



We calculate terms in parentheses: -(-3(x+2)-13), so:

-3(x+2)-13

We multiply parentheses

-3x-6-13

We add all the numbers together, and all the variables

-3x-19

Back to the equation:

-(-3x-19)



We add all the numbers together, and all the variables

6x-(-3x-19)+3=0

We get rid of parentheses

6x+3x+19+3=0

We add all the numbers together, and all the variables

9x+22=0

We move all terms containing x to the left, all other terms to the right

9x=-22

x=-22/9

x=-2+4/9

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