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2(3x-1)-2x=4(x+2)-3
We move all terms to the left:
2(3x-1)-2x-(4(x+2)-3)=0
We add all the numbers together, and all the variables
-2x+2(3x-1)-(4(x+2)-3)=0
We multiply parentheses
-2x+6x-(4(x+2)-3)-2=0
We calculate terms in parentheses: -(4(x+2)-3), so:We add all the numbers together, and all the variables
4(x+2)-3
We multiply parentheses
4x+8-3
We add all the numbers together, and all the variables
4x+5
Back to the equation:
-(4x+5)
4x-(4x+5)-2=0
We get rid of parentheses
4x-4x-5-2=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
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