2(3x-1)-3=3(2x+1)-8

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Solution for 2(3x-1)-3=3(2x+1)-8 equation: 



2(3x-1)-3=3(2x+1)-8

We move all terms to the left:

2(3x-1)-3-(3(2x+1)-8)=0

We multiply parentheses

6x-(3(2x+1)-8)-2-3=0



We calculate terms in parentheses: -(3(2x+1)-8), so:

3(2x+1)-8

We multiply parentheses

6x+3-8

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

6x-(6x-5)-5=0

We get rid of parentheses

6x-6x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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