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2(3x-1)=2(11x-1)
We move all terms to the left:
2(3x-1)-(2(11x-1))=0
We multiply parentheses
6x-(2(11x-1))-2=0
We calculate terms in parentheses: -(2(11x-1)), so:We get rid of parentheses
2(11x-1)
We multiply parentheses
22x-2
Back to the equation:
-(22x-2)
6x-22x+2-2=0
We add all the numbers together, and all the variables
-16x=0
x=0/-16
x=0
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