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2(3x-1)=2(x+1)
We move all terms to the left:
2(3x-1)-(2(x+1))=0
We multiply parentheses
6x-(2(x+1))-2=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
6x-2x-2-2=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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