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2(3x-1)=5(x+5)-3(x-1)
We move all terms to the left:
2(3x-1)-(5(x+5)-3(x-1))=0
We multiply parentheses
6x-(5(x+5)-3(x-1))-2=0
We calculate terms in parentheses: -(5(x+5)-3(x-1)), so:We get rid of parentheses
5(x+5)-3(x-1)
We multiply parentheses
5x-3x+25+3
We add all the numbers together, and all the variables
2x+28
Back to the equation:
-(2x+28)
6x-2x-28-2=0
We add all the numbers together, and all the variables
4x-30=0
We move all terms containing x to the left, all other terms to the right
4x=30
x=30/4
x=7+1/2
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