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2(3x-1)=5-(2x+3)
We move all terms to the left:
2(3x-1)-(5-(2x+3))=0
We multiply parentheses
6x-(5-(2x+3))-2=0
We calculate terms in parentheses: -(5-(2x+3)), so:We get rid of parentheses
5-(2x+3)
determiningTheFunctionDomain -(2x+3)+5
We get rid of parentheses
-2x-3+5
We add all the numbers together, and all the variables
-2x+2
Back to the equation:
-(-2x+2)
6x+2x-2-2=0
We add all the numbers together, and all the variables
8x-4=0
We move all terms containing x to the left, all other terms to the right
8x=4
x=4/8
x=1/2
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