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2(3x-1)=6(2+x)
We move all terms to the left:
2(3x-1)-(6(2+x))=0
We add all the numbers together, and all the variables
2(3x-1)-(6(x+2))=0
We multiply parentheses
6x-(6(x+2))-2=0
We calculate terms in parentheses: -(6(x+2)), so:We get rid of parentheses
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
6x-6x-12-2=0
We add all the numbers together, and all the variables
-14!=0
There is no solution for this equation
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