2(3x-1/2)+2(5x-2)=2(2x+3)+10x-5

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Solution for 2(3x-1/2)+2(5x-2)=2(2x+3)+10x-5 equation:



2(3x-1/2)+2(5x-2)=2(2x+3)+10x-5
We move all terms to the left:
2(3x-1/2)+2(5x-2)-(2(2x+3)+10x-5)=0
We add all the numbers together, and all the variables
2(+3x-1/2)+2(5x-2)-(2(2x+3)+10x-5)=0
We multiply parentheses
6x+10x-(2(2x+3)+10x-5)-4-1/2*2=0
We multiply all the terms by the denominator
6x*2*2+10x*2*2-((2(2x+3)+10x-5))*2*2-1-4*2*2=0
We add all the numbers together, and all the variables
6x*2*2+10x*2*2-((2(2x+3)+10x-5))*2*2-17=0
Wy multiply elements
24x*2+40x*2-((2(2x+3)+10x-5))*2*2-17=0
Wy multiply elements
48x+80x-((2(2x+3)+10x-5))*2*2-17=0
We add all the numbers together, and all the variables
128x-((2(2x+3)+10x-5))*2*2-17=0
We move all terms containing x to the left, all other terms to the right
128x-((2(2x+3)+10x-5))*2*2=17

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