2(3x-10)+8=8x+12

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Solution for 2(3x-10)+8=8x+12 equation: 



2(3x-10)+8=8x+12

We move all terms to the left:

2(3x-10)+8-(8x+12)=0

We multiply parentheses

6x-(8x+12)-20+8=0

We get rid of parentheses

6x-8x-12-20+8=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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