2(3x-12)=41

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Solution for 2(3x-12)=41 equation: 



2(3x-12)=41

We move all terms to the left:

2(3x-12)-(41)=0

We multiply parentheses

6x-24-41=0

We add all the numbers together, and all the variables

6x-65=0

We move all terms containing x to the left, all other terms to the right

6x=65

x=65/6

x=10+5/6

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