2(3x-13)=40-3(x-5)

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Solution for 2(3x-13)=40-3(x-5) equation: 



2(3x-13)=40-3(x-5)

We move all terms to the left:

2(3x-13)-(40-3(x-5))=0

We multiply parentheses

6x-(40-3(x-5))-26=0



We calculate terms in parentheses: -(40-3(x-5)), so:

40-3(x-5)

determiningTheFunctionDomain
-3(x-5)+40

We multiply parentheses

-3x+15+40

We add all the numbers together, and all the variables

-3x+55

Back to the equation:

-(-3x+55)



We get rid of parentheses

6x+3x-55-26=0

We add all the numbers together, and all the variables

9x-81=0

We move all terms containing x to the left, all other terms to the right

9x=81

x=81/9

x=9

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